struts2--使用自定义拦截器

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引言:做一个后台管理系统,这个系统为企业内部系统,如果不登录时没有权限访问此系统的。这时,可以使用拦截器拦截非法登录的用户。

自定义拦截器需要实现接口com.opensymphony.xwork2.interceptor.Interceptor。当然struts2提供了接口的实现类AbstractInterceptor,继承之,重新方法即可。

拦截器代码:

package com.Interceptor;import com.opensymphony.xwork2.ActionContext;import com.opensymphony.xwork2.ActionInvocation;import com.opensymphony.xwork2.interceptor.AbstractInterceptor;public class LoginInterceptor extends AbstractInterceptor{@Overridepublic String intercept(ActionInvocation invocation) throws Exception { String user =  (String) ActionContext.getContext().getSession().get("user"); if(null == user){ ActionContext actionContext = invocation.getInvocationContext();//也可ActionContext.getContext();获取 actionContext.put("tishi", "您还没有登录!请先登录!"); return "login"; } return invocation.invoke() ;//用户已经登录,进行后续操作} }

struts.xml配置:

<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE struts PUBLIC    "-//Apache Software Foundation//DTD Struts Configuration 2.1.7//EN"    "http://struts.apache.org/dtds/struts-2.1.7.dtd">    <struts> <package name="default" namespace = "/" extends = "struts-default">    <interceptors>      <interceptor name="loginInterceptor" class="com.Interceptor.LoginInterceptor"/>      <interceptor-stack name="myStack">        <interceptor-ref name="loginInterceptor"/>        <interceptor-ref name="defaultStack"/>      </interceptor-stack>    </interceptors>        <default-interceptor-ref name="myStack"/>         <action name="login" class = "com.action.LoginAction">       <result name = "success">/ok.jsp</result>       <result name = "login">/index.jsp</result>       <interceptor-ref name="defaultStack"/>     </action>          <action name="check" class = "com.action.CheckAction">       <result name = "success">/check_ok.jsp</result>       <result name = "login">/index.jsp</result>     </action>  </package></struts>    
在Action中引用拦截器,则默认拦截器将不起作用;由于登录方法不需要拦截,故不需要拦截器。


LoginAction.java

package com.action;import com.opensymphony.xwork2.ActionContext;import com.opensymphony.xwork2.ActionSupport;@SuppressWarnings("serial")public class LoginAction extends ActionSupport{  private String username;  private String password ;public String execute() {  if(username.equals("admin") && password.equals("admin")){  ActionContext.getContext().getSession().put("user", username);  return SUCCESS;  }else {  return LOGIN;  }}  public String getUsername() {return username;}public void setUsername(String username) {this.username = username;}public String getPassword() {return password;}public void setPassword(String password) {this.password = password;}  }

登录界面:index.jsp

<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%><%@ taglib prefix = "s" uri = "/struts-tags" %><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html>  <head>    <base href="<%=basePath%>">        <title>My JSP 'index.jsp' starting page</title><meta http-equiv="pragma" content="no-cache"><meta http-equiv="cache-control" content="no-cache"><meta http-equiv="expires" content="0">    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"><meta http-equiv="description" content="This is my page"><!--<link rel="stylesheet" type="text/css" href="styles.css">-->  </head>    <body>  <s:property value = "tishi"/>  <form action="login" method = "post">    <s:textfield name = "username" label = "用户名"></s:textfield><br><br>    <s:password name = "password" label = "密码"></s:password><br><br>    <s:submit value = "登录"></s:submit>   </form>  </body></html>

通常我们会遇到一段时间后刷新网页需要重新登录,也是拦截器在起作用,此时需要在web.xml中配置session作用的时间。

  <session-config>    <session-timeout>1</session-timeout>  </session-config>
一分钟后失效