对Pandas for 2.7生成的字符串 C#在接收时的解决方法

来源：互联网发布：js做一个弹窗编辑：程序博客网时间：2024/06/06 17:32

今天在Pandas for Python2.7 下生成的 .to_json方法，出来如下内容：

{"\u822a\u7ebf":{},"1\u3001\u627e\u5df2\u6709\u579b\u4f4d":{},"1\u3001\u5b89\u6392\u6570\u91cf":{},"2\u3001\u5f00\u65b0\u579b\u4f4d":{},"2\u3001\u5b89\u6392\u6570\u91cf":{},"3\u3001\u94c1\u5e95\u579b":{},"3\u3001\u5b89\u6392\u6570\u91cf":{},"4\u3001\u6df7'Q4-45'\u579b":{},"4\u3001'Q4-45'\u6570\u91cf":{},"5\u3001\u6df7\u579b":{},"5\u3001\u5b89\u6392\u6570\u91cf":{},"\u603b\u5728\u9014\u91cf":{},"\u9884\u8ba1\u843d\u5730\u91cf":{},"\u672a\u5b89\u6392\u91cf":{},"\u8239\u72b6\u6001":{}}

在C#中通过WebService解决这种问题，调用一下函数即可。

 public static string UnicodeToGB(string text)    {        System.Text.RegularExpressions.MatchCollection mc = System.Text.RegularExpressions.Regex.Matches(text, "\\\\u([\\w]{4})");        if (mc != null && mc.Count > 0)        {            foreach (System.Text.RegularExpressions.Match m2 in mc)            {                string v = m2.Value;                string word = v.Substring(2);                byte[] codes = new byte[2];                int code = Convert.ToInt32(word.Substring(0, 2), 16);                int code2 = Convert.ToInt32(word.Substring(2), 16);                codes[0] = (byte)code2;                codes[1] = (byte)code;                text = text.Replace(v, Encoding.Unicode.GetString(codes));            }        }        else        {        }        return text;    }

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