1107. Social Clusters (30)并查集
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When register on a social network, you are always asked to specify your hobbies in order to find some potential friends with the same hobbies. A “social cluster” is a set of people who have some of their hobbies in common. You are supposed to find all the clusters.
Input Specification:
Each input file contains one test case. For each test case, the first line contains a positive integer N (<=1000), the total number of people in a social network. Hence the people are numbered from 1 to N. Then N lines follow, each gives the hobby list of a person in the format:
Ki: hi[1] hi[2] … hi[Ki]
where Ki (>0) is the number of hobbies, and hi[j] is the index of the j-th hobby, which is an integer in [1, 1000].
Output Specification:
For each case, print in one line the total number of clusters in the network. Then in the second line, print the numbers of people in the clusters in non-increasing order. The numbers must be separated by exactly one space, and there must be no extra space at the end of the line.
Sample Input:
8
3: 2 7 10
1: 4
2: 5 3
1: 4
1: 3
1: 4
4: 6 8 1 5
1: 4
Sample Output:
3
4 3 1
#include<iostream>#include<map>#include<cstdio>#include<algorithm>using namespace std;int father[1001];int find(int x){ if (x==father[x]) return x; return father[x]=find(father[x]);}bool cmp(int a,int b){ return a>b;}int a[1005],out[1005],index1=0;int n;map<int ,int > ma;int main(){ cin>>n; for (int i=1;i<=1000;i++) { father[i]=i; } for(int i=1;i<=n;i++) { int sum,temp; scanf("%d: ",&sum); scanf("%d",&temp); a[i]=temp; temp=find(temp); for (int j=1;j<sum;j++) { int nu; scanf("%d",&nu); nu=find(nu); father[nu]=temp; } } for(int i=1;i<=n;i++) { ma[find(a[i])]++; } for (map<int ,int > ::iterator it=ma.begin();it!=ma.end();it++) { out[index1++]=it->second; } sort(out,out+index1,cmp); cout<<index1<<endl; for (int i=0;i<index1;i++) { cout<<out[i]; if (i!=index1-1) { cout<<" "; } } return 0;}
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