function and pointer

Recently,I've solved a problem about equation using function and pointer. I've thought out two ways to solve it.Here's my code.

#include <stdio.h>
#include<math.h>
int Finding(double a,double b,double c,double delta,double *x1,double*x2)
{
double d=sqrt(delta);
*x1=(-b-d)/(2*a);
*x2=(-b+d)/(2*a);
return 0;
}
int main()
{
double x1,x2,a,b,c,delta;
scanf("%lf%lf%lf",&a,&b,&c);
delta=b*b-4*a*c;
Finding(a,b,c,delta,&x1,&x2);
if(delta<0) printf("ERROR");
if(delta==0) printf("%.2f",x1);
if(delta>0) printf("%.2f\n%.2f\n",x1,x2);
return 0;
}

#include<stdio.h>
#include<math.h>
double Delta(double a,double b,double c)
{
return b*b-4*a*c;
}
int Solver(double a,double b,double c,double *x1,double *x2)
{
int flag=0;
double d=Delta(a,b,c);
if(d>=0)
{
d=sqrt(d);
*x1=(-b-d)/(2*a);
*x2=(-b+d)/(2*a);
flag=(d>0)?2:1;
}
return flag;
}


int main()
{
double a,b,c,x1,x2;
scanf("%lf%lf%lf",&a,&b,&c);
int flag;
flag=Solver(a,b,c,&x1,&x2);
switch(flag)
{
case 0: printf("ERROR\n"); break;
case 1: printf("x1=x2=%.2f\n"); break;
case 2: printf("x1=%.2f\nx2=%.2f\n",x1,x2); break;
}
return 0;
}

Attention:the pointer can deliver the address of variable even if the variable isn't assigned.