将N个字符的数组，循环右移K位。时间复杂度O(N)

将N个字符的数组，循环右移K位。时间复杂度O(N)
比如：str[]=”abcde123”,右移3位
1、旋转abcde->edcba
2、旋转123->321
3、整体旋转abcde123->123abcde

void reverse(char *str, int left, int right){    while (left<right)    {        char tmp = str[right];         str[left] = str[right];        str[right] = tmp;        left++;        right--;    }}void rightMove(char *str, int length, int k){    k = k%length;    //旋转前k个字符    reverse(str, 0, length - k - 1);    //旋转剩余字符    reverse(str, length - k, length - 1);    //整体旋转    reverse(str, 0, length - 1);}