RMS遍历问题

来源：互联网发布：淘宝怎么抢秒杀商品编辑：程序博客网时间：2024/05/29 18:36

try {
   rs = RecordStore.openRecordStore("rs", true);
   rs.addRecord("龙".getBytes(), 0, 2);
   System.out.println("第二章,,呵呵,,123".getBytes().length);
   rs.addRecord("虎".getBytes(), 0, 2);
   rs.addRecord("狍".getBytes(), 0, 2);
   rs.addRecord("蛇".getBytes(), 0, 2);
   rs.addRecord("老鼠".getBytes(), 0, 4);
   rs.deleteRecord(4);

   // 方法一，枚举遍历
//   RecordEnumeration re = rs.enumerateRecords(null, null, false); // 能发现失效的ID并自动跳过
//   while (re.hasNextElement()) {
//    System.out.println(new String(re.nextRecord()));
//   }

   // 方法二，getNextRecordID,遍历ID
   for (int i = 1; i < rs.getNextRecordID(); i++) {
    try {
     System.out.println(new String(rs.getRecord(i)));
    } catch (Exception e) {
    } // 忽略异常
   }

  } catch (RecordStoreFullException e) {
   e.printStackTrace();
  } catch (RecordStoreNotFoundException e) {
   e.printStackTrace();
  } catch (RecordStoreException e) {
   e.printStackTrace();
  }