hdu 6092 Rikka with Subset 背包(贪心)
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Rikka with Subset
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Problem Description
As we know, Rikka is poor at math. Yuta is worrying about this situation, so he gives Rikka some math tasks to practice. There is one of them:
Yuta hasn positive A1−An and their sum is m . Then for each subset S of A , Yuta calculates the sum of S .
Now, Yuta has got2n numbers between [0,m] . For each i∈[0,m] , he counts the number of i s he got as Bi .
Yuta shows Rikka the arrayBi and he wants Rikka to restore A1−An .
It is too difficult for Rikka. Can you help her?
Yuta has
Now, Yuta has got
Yuta shows Rikka the array
It is too difficult for Rikka. Can you help her?
Input
The first line contains a number t(1≤t≤70) , the number of the testcases.
For each testcase, the first line contains two numbersn,m(1≤n≤50,1≤m≤104) .
The second line containsm+1 numbers B0−Bm(0≤Bi≤2n) .
For each testcase, the first line contains two numbers
The second line contains
Output
For each testcase, print a single line with n numbers A1−An .
It is guaranteed that there exists at least one solution. And if there are different solutions, print the lexicographic minimum one.
It is guaranteed that there exists at least one solution. And if there are different solutions, print the lexicographic minimum one.
Sample Input
22 31 1 1 13 31 3 3 1
Sample Output
1 21 1 1HintIn the first sample, $A$ is $[1,2]$. $A$ has four subsets $[],[1],[2],[1,2]$ and the sums of each subset are $0,1,2,3$. So $B=[1,1,1,1]$
import java.io.BufferedReader;import java.io.InputStream;import java.io.InputStreamReader;import java.io.PrintWriter;import java.math.BigInteger;import java.util.Arrays;import java.util.StringTokenizer;public class Main { public static void main(String[] args) { new Task().solve(); }}class Task { InputReader in = new InputReader(System.in) ; PrintWriter out = new PrintWriter(System.out) ; void solve(){ int t = in.nextInt() ; while(t-- > 0){ int n = in.nextInt() ; int m = in.nextInt() ; long[] B = new long[m+1] ; int sum = 0 ; for(int i = 0 ; i <= m ; i++){ B[i] = in.nextLong() ; } long[] dp = new long[m+1] ; Arrays.fill(dp, 0) ; dp[0] = 1 ; boolean fisrt = true ; int d = 0 ; for(int i = 1 ; i <= m ; i++){ long cnt = B[i] - dp[i] ; if(cnt <= 0){ continue ; } for(int k = 0 ; k < cnt ; k++){ out.print(fisrt ? "" : " ") ; out.print(i) ; fisrt = false ; for(int j = m ; j >= i ; j--){ dp[j] += dp[j-i] ; } } } out.println() ; } out.flush() ; }}class InputReader { public BufferedReader reader; public StringTokenizer tokenizer; public InputReader(InputStream stream) { reader = new BufferedReader(new InputStreamReader(stream), 32768); tokenizer = new StringTokenizer(""); } private void eat(String s) { tokenizer = new StringTokenizer(s); } public String nextLine() { try { return reader.readLine(); } catch (Exception e) { return null; } } public boolean hasNext() { while (!tokenizer.hasMoreTokens()) { String s = nextLine(); if (s == null) return false; eat(s); } return true; } public String next() { hasNext(); return tokenizer.nextToken(); } public int nextInt() { return Integer.parseInt(next()); } public int[] nextInts(int n) { int[] nums = new int[n]; for (int i = 0; i < n; i++) { nums[i] = nextInt(); } return nums; } public long nextLong() { return Long.parseLong(next()); } public double nextDouble() { return Double.parseDouble(next()); } public BigInteger nextBigInteger() { return new BigInteger(next()); } }卡的好严,多了减法就TLE
import java.io.BufferedReader;import java.io.InputStream;import java.io.InputStreamReader;import java.io.PrintWriter;import java.math.BigInteger;import java.util.Arrays;import java.util.StringTokenizer;public class Main { public static void main(String[] args) { new Task().solve(); }}class Task { InputReader in = new InputReader(System.in) ; PrintWriter out = new PrintWriter(System.out) ; void solve(){ int t = in.nextInt() ; while(t-- > 0){ int n = in.nextInt() ; int m = in.nextInt() ; long[] B = new long[m+1] ; int sum = 0 ; for(int i = 0 ; i <= m ; i++){ B[i] = in.nextLong() ; } long[] dp = new long[m+1] ; Arrays.fill(dp, 0) ; dp[0] = 1 ; boolean fisrt = true ; int d = 0 ; for(int i = 1 ; i <= m ; i++){ long cnt = B[i] ; if(cnt <= 0){ continue ; } for(int k = 0 ; k < cnt ; k++){ out.print(fisrt ? "" : " ") ; out.print(i) ; fisrt = false ; for(int j = m ; j >= i ; j--){ dp[j] += dp[j-i] ; B[j] -= dp[j] ; } } } out.println() ; } out.flush() ; }}class InputReader { public BufferedReader reader; public StringTokenizer tokenizer; public InputReader(InputStream stream) { reader = new BufferedReader(new InputStreamReader(stream), 32768); tokenizer = new StringTokenizer(""); } private void eat(String s) { tokenizer = new StringTokenizer(s); } public String nextLine() { try { return reader.readLine(); } catch (Exception e) { return null; } } public boolean hasNext() { while (!tokenizer.hasMoreTokens()) { String s = nextLine(); if (s == null) return false; eat(s); } return true; } public String next() { hasNext(); return tokenizer.nextToken(); } public int nextInt() { return Integer.parseInt(next()); } public int[] nextInts(int n) { int[] nums = new int[n]; for (int i = 0; i < n; i++) { nums[i] = nextInt(); } return nums; } public long nextLong() { return Long.parseLong(next()); } public double nextDouble() { return Double.parseDouble(next()); } public BigInteger nextBigInteger() { return new BigInteger(next()); } }
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