HDU 1012

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 47303    Accepted Submission(s): 21729

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

n e- -----------0 11 22 2.53 2.6666666674 2.708333333
#include <stdio.h>double fac(int i){if(i==0||i==1) return 1;else return  i*fac(i-1);}int main(){double sum=0;printf("n e\n- -----------\n");for(int i=0;i<=9;i++){sum += 1/fac(i);if(i==0||i==1)printf("%d %.0lf\n",i,sum);else if(i==2)printf("%d %.1lf\n",i,sum);elseprintf("%d %.9lf\n",i,sum);}sum=0;}