[LeetCode]237. Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

我的解法：同I copied every node.val to the one before and set the last one to null. What a shame.

/** * Definition for singly-linked list. * public class ListNode { *     int val; *     ListNode next; *     ListNode(int x) { val = x; } * } */public class Solution {    public void deleteNode(ListNode node) {        while(node.next.next!=null){            node.val=node.next.val;            node=node.next;        }        node.val=node.next.val;        node.next=null;    }}

聪明的解法：只把要删除的节点后面的那个的值赋过来，然后删除后面那个节点。

public void deleteNode(ListNode node) {    node.val = node.next.val;    node.next = node.next.next;}