Common Subsequence

子串：

对于一个字符串变量，例如"adereegfbw",它的子串就是像"ader"这样可以从中找到的连续的字符串。字符串"adereegfbw"本身也属于它本身最长的子串。（摘自百度百科）

子序列：

在数学中，某个序列的子序列是从最初序列通过去除某些元素但不破坏余下元素的相对位置（在前或在后）而形成的新序列。（摘自维基百科）

Description

A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if there exists a strictly increasing sequence < i1, i2, ..., ik > of indices of X such that for all j = 1,2,...,k, x_ij = zj. For example, Z = < a, b, f, c > is a subsequence of X = < a, b, c, f, b, c > with index sequence < 1, 2, 4, 6 >. Given two sequences X and Y the problem is to find the length of the maximum-length common subsequence of X and Y.

Input

The program input is from the std input. Each data set in the input contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct.

Output

For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.

Sample Input

abcfbc      abfcabprogramming    contest abcd           mnp

Sample Output

420

#include<stdio.h>#include<string.h>#include<algorithm>#define maxn 1000using namespace std;int dp[maxn];int main(){char str1[maxn],str2[maxn];memset(str1,0,sizeof(str1));memset(str2,0,sizeof(str2));memset(dp,0,sizeof(dp));while(scanf("%s %s",str1,str2)!=EOF){int len1=strlen(str1),len2=strlen(str2);for(int i=0;i<len2;i++)for(int j=0;j<len1;j++)if(str2[i]==str1[j])dp[j+1]=dp[j]+1;elsedp[j+1]=max(dp[j+1],dp[j]);printf("%d\n",dp[len1]);}return 0;}