Game of the Rows CodeForces
来源:互联网 发布:三浦翔平人不好知乎 编辑:程序博客网 时间:2024/05/02 01:00
Game of the Rows
Daenerys Targaryen has an army consisting of k groups of soldiers, thei-th group contains ai soldiers. She wants to bring her army to the other side of the sea to get the Iron Throne. She has recently bought an airplane to carry her army through the sea. The airplane hasn rows, each of them has 8 seats. We call two seats neighbor, if they are in the same row and in seats{1, 2}, {3, 4}, {4, 5}, {5, 6} or {7, 8}.
Daenerys Targaryen wants to place her army in the plane so that there are no two soldiers from different groups sitting on neighboring seats.
Your task is to determine if there is a possible arranging of her army in the airplane such that the condition above is satisfied.
The first line contains two integers n andk (1 ≤ n ≤ 10000,1 ≤ k ≤ 100) — the number of rows and the number of groups of soldiers, respectively.
The second line contains k integers a1, a2, a3, ..., ak (1 ≤ ai ≤ 10000), where ai denotes the number of soldiers in thei-th group.
It is guaranteed that a1 + a2 + ... + ak ≤ 8·n.
If we can place the soldiers in the airplane print "YES" (without quotes). Otherwise print "NO" (without quotes).
You can choose the case (lower or upper) for each letter arbitrary.
2 25 8
YES
1 27 1
NO
1 24 4
YES
1 42 2 1 2
YES
In the first sample, Daenerys can place the soldiers like in the figure below:
In the second sample, there is no way to place the soldiers in the plane since the second group soldier will always have a seat neighboring to someone from the first group.
In the third example Daenerys can place the first group on seats (1, 2, 7, 8), and the second group an all the remaining seats.
In the fourth example she can place the first two groups on seats (1, 2) and (7, 8), the third group on seats (3), and the fourth group on seats (5, 6).
#include<stdio.h>#include<iostream>using namespace std;int str[10005];int main(){int n,k,ans1,ans2;while(cin>>n>>k){for(int i=0;i<k;i++)cin>>str[i];ans1=n;ans2=2*n;for(int i=0;i<k;i++){int t=min(str[i]/4,ans1);ans1-=t;str[i]-=4*t;}ans2+=ans1;for(int i=0;i<k;i++){int t=min(str[i]/2,ans2);ans2-=t;str[i]-=2*t;}ans2+=ans1;for(int i=0;i<k;i++)ans2-=str[i];if(ans2>=0)cout<<"YES"<<endl;elsecout<<"NO"<<endl;}return 0;}
- Game of the Rows CodeForces
- Game of the Rows CodeForces
- codeforces 839 B Game of the Rows
- Codeforces 839B-Game of the Rows
- Game of the Rows
- Game of the Rows
- Codeforces 839B Game of the Rows (贪心)
- Codeforces 839 B. Game of the Rows (贪心)
- Codeforces Round #428 (Div. 2) Game of the Rows (思维)
- Codeforces Round #428 (Div. 2) B. Game of the Rows
- Codeforces 839B Game of the Rows 贪心
- codeforces 839A 428 Div2 B Game of the Rows
- codeforces 839B Game of the Rows(思路题)
- Codeforces Round #428 (Div. 2) B. Game of the Rows
- CodeForces-839B Game of the Rows(思维、细节)
- codeforces 839b 之 Game of the Rows
- codeforces#839 B Game of the Rows 思维,贪心
- Game of the Rows codeforces 839B(贪心)
- poj-2773(数论+容斥原理+二分)
- Reader 和 Writer
- Linux设备驱动模型框架分析(五)——LDDM的展现:sysfs
- hdu 6127 计算几何模拟题(旋转扫描线)
- MFC内存绘图设备封装类
- Game of the Rows CodeForces
- 【yoyo】关于java中内部类的使用
- AngularJs学习之路(九)
- LeetCode200. Number of Islands 基础dfs
- MOOC清华《面向对象程序设计》第2章:函数参数的缺省值实验
- OpenCart 3.x版本简体中文语言包安装教程
- 怪盗基德的挑战书
- A water problem(大数取模)
- ajax属性详解(转载)