HDU

Combine String

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)
Total Submission(s): 2208    Accepted Submission(s): 623

Problem Description

Given three strings a, b and c, your mission is to check whether c is the combine string of a and b.
A string c is said to be the combine string of a and b if and only if c can be broken into two subsequences, when you read them as a string, one equals to a, and the other equals to b.
For example, ``adebcf'' is a combine string of ``abc'' and ``def''.

 

Input

Input file contains several test cases (no more than 20). Process to the end of file.
Each test case contains three strings a, b and c (the length of each string is between 1 and 2000).

 

Output

For each test case, print ``Yes'', if c is a combine string of a and b, otherwise print ``No''.

 

Sample Input

abcdefadebcfabcdefabecdf

 

Sample Output

YesNo

 

Source

"巴卡斯杯" 中国大学生程序设计竞赛 - 女生专场

 

Recommend

liuyiding

题意： 有a、b、c三个串，当且仅当a、b都为c的字串时输出yes，否则输出no

#include <bits/stdc++.h>const int N = 2e3 + 10;int dp[N][N];char a[N], b[N], c[N];int main(){    while(~scanf("%s %s %s",a , b, c))    {        memset(dp,0,sizeof(dp));        int flag=0;        int la = strlen(a), lb = strlen(b), lc = strlen(c);        dp[0][0] = 1;        for(int i = 0;i <= la; i++){            for(int j = 0; j <= lb; j++){                if(a[i] == c[i+j]){                    dp[i+1][j] |= dp[i][j];                }                if(b[j]==c[i+j]){                    dp[i][j+1] |= dp[i][j];                }            }        }        if(dp[la][lb] && lc == la + lb) printf("Yes\n");        else printf("No\n");    }}