Bone Collector *

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

Output

One integer per line representing the maximum of the total value (this number will be less than 2³¹).

Sample Input

15 101 2 3 4 55 4 3 2 1

Sample Output

14

比较裸的01背包

#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;typedef long long ll;const int maxn=1010;ll dp[maxn];int vol[maxn];int  w[maxn];int main(){   int T;   scanf("%d",&T);   while(T--)   {      memset(dp,0,sizeof(dp));      int n,v;      scanf("%d %d",&n,&v);      for(int i=1;i<=n;i++)        scanf("%d",&w[i]);      for(int i=1;i<=n;i++)        scanf("%d",&vol[i]);      for(int i=1;i<=n;i++)        for(int j=v;j>=vol[i];j--)            dp[j]=max(dp[j],dp[j-vol[i]]+w[i]);      printf("%I64d\n",dp[v]);   }   return 0;}