斐波那契数列

斐波那契数列

#include<iostream>int main(){    int i=0,n=0, ans[100]={0};    scanf("%d",&n);    ans[0] = 0;    ans[1] = 1;    for(i=2;i<=n;i++)    {        ans[i] = ans[i-1] + ans[i-2];        //printf("%d,%d\n",ans[i], i);    }    printf("%d\n",ans[n]);    return 0;}