称假币(枚举)
来源:互联网 发布:cf外国聊天软件 编辑:程序博客网 时间:2024/05/16 14:52
点击打开链接
Counterfeit Dollar
Time Limit: 1000MS Memory Limit: 10000KTotal Submissions: 47432 Accepted: 14994
Description
Sally Jones has a dozen Voyageur silver dollars. However, only eleven of the coins are true silver dollars; one coin is counterfeit even though its color and size make it indistinguishable from the real silver dollars. The counterfeit coin has a different weight from the other coins but Sally does not know if it is heavier or lighter than the real coins.
Happily, Sally has a friend who loans her a very accurate balance scale. The friend will permit Sally three weighings to find the counterfeit coin. For instance, if Sally weighs two coins against each other and the scales balance then she knows these two coins are true. Now if Sally weighs
one of the true coins against a third coin and the scales do not balance then Sally knows the third coin is counterfeit and she can tell whether it is light or heavy depending on whether the balance on which it is placed goes up or down, respectively.
By choosing her weighings carefully, Sally is able to ensure that she will find the counterfeit coin with exactly three weighings.
Happily, Sally has a friend who loans her a very accurate balance scale. The friend will permit Sally three weighings to find the counterfeit coin. For instance, if Sally weighs two coins against each other and the scales balance then she knows these two coins are true. Now if Sally weighs
one of the true coins against a third coin and the scales do not balance then Sally knows the third coin is counterfeit and she can tell whether it is light or heavy depending on whether the balance on which it is placed goes up or down, respectively.
By choosing her weighings carefully, Sally is able to ensure that she will find the counterfeit coin with exactly three weighings.
Input
The first line of input is an integer n (n > 0) specifying the number of cases to follow. Each case consists of three lines of input, one for each weighing. Sally has identified each of the coins with the letters A--L. Information on a weighing will be given by two strings of letters and then one of the words ``up'', ``down'', or ``even''. The first string of letters will represent the coins on the left balance; the second string, the coins on the right balance. (Sally will always place the same number of coins on the right balance as on the left balance.) The word in the third position will tell whether the right side of the balance goes up, down, or remains even.
Output
For each case, the output will identify the counterfeit coin by its letter and tell whether it is heavy or light. The solution will always be uniquely determined.
Sample Input
1 ABCD EFGH even ABCI EFJK up ABIJ EFGH even
Sample Output
K is the counterfeit coin and it is light.
Source
East Central North America 1998
解题思路
对于每一枚硬币先假设它是轻的,看这样是否符合称量结果。如果符合,
问题即解决。如果不符合,就假设它是重的,看是否符合称量结果。把所有硬币都
试一遍,一定能找到特殊硬币
代码实现
#include <iostream> #include <cstring> using namespace std; char Left[3][7]; //天平左边硬币 char Right[3][7]; //天平右边硬币 char result[3][7]; //结果 bool IsFake(char c,bool light) ; //light 为真表示假设假币为轻,否则表示假设假币为重 int main() { int t; cin >> t; while(t--) { for(int i = 0;i < 3; ++i) cin >> Left[i] >> Right[i] >> result[i]; for(char c='A'; c<='L';c++) { if( IsFake(c,true) ){ cout << c << " is the counterfeit coin and it is light.\n"; break; } else if( IsFake(c,false) ){ cout << c << " is the counterfeit coin and it is heavy.\n"; break; } } } return 0; } bool IsFake(char c,bool light) //light 为真表示假设假币为轻,否则表示假设假币为重 { for(int i = 0;i < 3; ++i) { char * pLeft,*pRight; //指向天平两边的字符串 if(light) { pLeft = Left[i]; pRight = Right[i]; } else { pLeft = Right[i]; pRight = Left[i]; }switch(result[i][0]) { case 'u': if ( strchr(pRight,c) == NULL) return false; break; case 'e': if( strchr(pLeft,c) || strchr(pRight,c)) return false; break; case 'd': if ( strchr(pLeft,c) == NULL) return false; break; } } return true; }
阅读全文
0 0
- 称假币(枚举)
- 假币问题(枚举)
- 面试:称硬币找假币的问题
- 称砝码(搜索\暴力枚举)
- 枚举—案例(称硬币poj1013)
- 枚举:称硬币问题
- 假币
- 枚举——称硬币
- N个硬币_其中一个假币_不知偏轻或偏重__称K次_找出假币
- OpenJudge百炼-2692-假币问题-C语言-枚举
- 央行通报最新百元假币特征 称凭眼看手摸可识别
- 有101枚硬币,100真,1假,若称两次,怎么求出假币
- 算法学习之枚举--称硬币
- 算法题----称硬币: 2n(并不要求n是2的幂次方)个硬币,有两个硬币重量为m+1, m-1, 其余都是m 分治 O(lgn)找出假币
- 101个硬币中有一个假币,有一个无砝码的天平,称两次,判断假币比真币重还是轻。
- HPUOJ 题目1079 假币问题(三分)
- oj 1903: 有假币(递归)
- n枚硬币找出假币问题(包含一枚假币)
- 构造注入和集合
- Mybatis 工具类
- python3 常用数据类型转换
- Http 协议 ----- 片段
- 京东-笔试题
- 称假币(枚举)
- maven的依赖
- malloc笔记
- spring自动代理
- SpringBoot自动配置的实现原理
- select特殊属性(selectedIndex,multiple)
- 一点编码规范心得
- 写一些记录博客
- java单点登录