数组实现斐波那契数列

#include<stdio.h>#include<stdlib.h>//斐波那契数列void main2(){int num[30];num[0] = 1;num[1] = 2;for (int i = 2; i < 30; i++){num[i] = num[i - 1] + num[i - 2];printf("%d\n", num[i]);}system("pause");}