hdu_4350_数组模拟_函数调用数组

Card
Bearchild is playing a card game with himself. But first of all, he needs to shuffle the cards. His strategy is very simple: After putting all the cards into a single stack,
he takes out some cards in the middle, from the L-th to the R-th when counting from top to bottom, inclusive, and puts them on the top. He repeats this action again
and again for N times, and then he regards his cards as shuffled.

Given L,R and N, and the initial card stack, can you tell us what will the card stack be like after getting shuffled?
Input
First line contains an integer T(1 <= T <= 1000), which is the test cases.
For each test case, first line contains 52 numbers(all numbers are distinct and between 1 and 52), which is the card number of the stack, from top to bottom.
Then comes three numbers, they are N, L and R as described. (0<=N<=109, 1<=L<=R<=52)
Output
For each test case, output “Case #X:”, X is the test number, followed by 52 numbers, which is the card number from the top to bottom.Note that you should output one and only
one blank before every number.
Sample Input
1
13 2 10 50 1 28 37 32 30 46 19 47 33 41 24 52 27 42 49 18 9 48 23 35 31 8 7 12 6 5 3 22 43 36 51 40 26 4 44
17 39 38 15 14 25 16 29 20 21 45 11 34
902908328 38 50
Sample Output
Case #1: 26 4 44 17 39 38 15 14 25 16 29 20 21 45 13 2 10 50 1 28 37 32 30 46 19 47 33 41 24 52 27 42 49 18
9 48 23 35 31 8 7 12 6 5 3 22 43 36 51 40 11 34
Source
2012 Multi-University Training Contest 6

题意:
给你52个不同的数,将从L–R的数移到52个数的开头,(包括L,R)重复操作n次,输出n次操作后的52个数;
思路:
找循环节,先模拟找到循环节,一切都出来,

#include<iostream>#include<cstdio>#include<map>#include<cstring>#include<algorithm>#include<cmath>typedef long long ll;using namespace  std;int n,l,r;void fun(int arr[]){    int a[111],i;    for(i=1;i<=52;i++)        a[i]=arr[i];    int len=r-l+1;    int tmp=l;    for(i=1;i<1+len;i++)        arr[i]=a[tmp++];    tmp=1;    for(i=1+len;i<=r;i++)        arr[i]=a[tmp++];}bool same(int tarr[],int arr[]){    for(int i=1;i<=52;i++)        if(tarr[i]!=arr[i])            return false;    return true;}int main(){    int t,i,j,arr[66],tarr[66];    while(cin>>t)    {        for(int c=1; c<=t; c++)        {            for(i=1; i<=52; i++)            {                scanf("%d",arr+i);                tarr[i]=arr[i];            }            scanf("%d%d%d",&n,&l,&r);            printf("Case #%d:",c);            int cnt=0;            while(1)            {                cnt++;                fun(arr);                if(same(tarr,arr))                    break;            }            int tmp=n%cnt;          //  cout<<tmp<<endl;            for(i=0; i<tmp; i++)                fun(tarr);            for(i=1; i<=52; i++)                printf(" %d",tarr[i]);            puts("");        }    }    return 0;}