HDU 2147-kiki's game
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kiki's game
Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 40000/10000 K (Java/Others)Total Submission(s): 11339 Accepted Submission(s): 6871
题目链接:点击打开链接
Problem Description
Recently kiki has nothing to do. While she is bored, an idea appears in his mind, she just playes the checkerboard game.The size of the chesserboard is n*m.First of all, a coin is placed in the top right corner(1,m). Each time one people can move the coin into the left, the underneath or the left-underneath blank space.The person who can't make a move will lose the game. kiki plays it with ZZ.The game always starts with kiki. If both play perfectly, who will win the game?
Input
Input contains multiple test cases. Each line contains two integer n, m (0<n,m<=2000). The input is terminated when n=0 and m=0.
Output
If kiki wins the game printf "Wonderful!", else "What a pity!".
Sample Input
5 3
5 4
6 6
0 0
Sample Output
What a pity!
Wonderful!
Wonderful!
5 3
5 4
6 6
0 0
Sample Output
What a pity!
Wonderful!
Wonderful!
题意:给你一个n*m的棋盘,起始位置在棋盘的右上角,然后可以往左往下往左下三个方向走,kiki先走,直到走到棋盘的左下角为止,最后走不了的玩家输,也就是走到左下角的玩家赢。
分析:本题是一个简单的博弈题,由PN图可知,n和m都为奇数时,kiki会输,其余情况他都会赢。
#include <iostream>#include<stdio.h>#include<cmath>using namespace std;int main(){ int n,m; while(scanf("%d %d",&n,&m)) { if(n==0&&m==0) break; if(n%2==1&&m%2==1) printf("What a pity!\n"); else printf("Wonderful!\n"); } return 0;}
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