codility TapeEquilibrium

Question:codility Lesson3 TapeEquilibrium

My answer:

def solution(A):    part1 = A[0]    part2 = sum(A[1:])    minres = abs(part1 - part2)    for i in range(1,len(A) - 1):        part1 += A[i]        part2 -= A[i]        if abs(part1 - part2) < minres:            minres = abs(part1 - part2)    return minres