codility MaxCounters

Question:codility Lesson4 MaxCounters

My answer:

def solution(N,A):    res = [0] * N    maxnum = 0    curmax = 0    for com in A:        if 1 <= com <= N:            if maxnum > res[com - 1]:                res[com -1] = maxnum            res[com - 1] += 1            if curmax < res[com - 1]:                curmax = res[com - 1]        else:            maxnum = curmax    for i in range(0,N):        if res[i] < maxnum:            res[i] = maxnum    return res