右键弹出窗口位置

//控件在其父控件中的位置
            Vector p = VisualTreeHelper.GetOffset(lblName);


            Point Point = new Point(p.X, p.Y);


            //相对于屏幕的位置
            Point pointScreen = (lblName.Parent as Visual).PointToScreen(Point);


            //屏幕位置
            aa.Location = new System.Drawing.Point(Convert.ToInt32(pointScreen.X - 200), Convert.ToInt32(pointScreen.Y + lblName.ActualHeight));