判断是否为连续的数字拼接而成的字符串

    public static void main(String[] args) {        //此种情况已经明确是数字拼接而成,如果可能含有非数字的情况,需要先判断是否全部为数字        String str1= "00001,00002";         String[] split = str1.split(",");        for (int i = 0; i < split.length; i++) {            System.out.println(split[i]);        }        System.out.println("------------");        for (int i = 0; i < split.length; i++) {            System.out.println("split["+i+"]="+split[i]);            if (i < split.length-1) {                BigDecimal num1 = new BigDecimal(split[i]);                BigDecimal num2 = new BigDecimal(split[i+1]);                System.out.println("num1为"+num1+";num2为"+num2+";num1+1之后的结果为"+num1.add(new BigDecimal("1"))+";num1+1与num2的比较结果为"+ num1.add(new BigDecimal("1")).compareTo(num2));                //比较结果为0时,表示相等                if (num1.add(new BigDecimal("1")).compareTo(num2) == 0) {                    System.out.println(num1.add(new BigDecimal("1")));                    System.out.println(num2);                }            }            System.out.println("------------");        }       }