Working Hours UVALive

来源：互联网发布：软件测试工程师薪水编辑：程序博客网时间：2024/05/08 21:22

题目链接：点击打开链接

思路：将所有时间化成分钟进行加减计算，输出时再转化成h:mm的形式即可。

代码：

#include<iostream>#include<iomanip>#include<sstream>#include<string>#include<algorithm>#include<vector>#include<list>#include<stack>#include<map>#include<set>#include<queue>#include<cstdio>#include<cstdlib>#include<cmath>#include<cstring>using namespace std;typedef long long ll;typedef long double ld;typedef pair<int,int> pii;#define rep(a,b,c) for(int (a)=(b);(a)<=(c);(a)++)#define drep(a,b,c) for(int (a)=(c);(a)>=(b);(a)--)char s[20];int main(){    int ok=0;    while(1)    {        int sum[2]={0};        int ssum=0;        while(scanf("%s",s)==1)        {            if(strcmp(s,"$$$")==0) break;            else if(strcmp(s,"###")==0)            {                ok=1;                break;            }            else            {                sum[0]=sum[1]=0;                int kg=0;                int l=strlen(s);                int zf=1;                for(int i=0;i<l;i++)                {                    if(s[i]=='+')                    {                        zf=1;                    }                    else if(s[i]=='-')                    {                        zf=-1;                    }                    else if(s[i]=='.')                    {                        sum[kg]*=60;                        kg++;                    }                    else if(s[i]==':')                    {                        sum[kg]*=60;                        kg++;                    }                    else                    {                        sum[kg]=sum[kg]*10+s[i]-'0';                    }                }                if(zf==1)                ssum+=(sum[0]+sum[1]);                else ssum-=(sum[0]+sum[1]);            }        }        int ttt=(ssum>=0)?1:-1;        ssum=abs(ssum-0);        int t=ssum/60;        int tt=ssum%60;        if(ttt==1)        {            if(tt<10) printf("%d:0%d\n",t,tt);            else printf("%d:%d\n",t,tt);        }        else        {            if(tt<10) printf("-%d:0%d\n",t,tt);            else printf("-%d:%d\n",t,tt);        }        if(ok) break;    }    return 0;}

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