（二分）cup

来源：互联网发布：西北师范大学知行诱骗编辑：程序博客网时间：2024/06/03 18:03

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AC代码：

#include <iostream>#include <cmath>#include<cstdio>using namespace std;const double p = acos(-1.0);int main(){    double r1, r2, h, v;    int t;    cin >> t;    double h1, h2;    double mid;    while (t--)    {        cin >> r1 >> r2 >> h >> v;        h1 = 0;        h2 = h + 1e-6;        while (h2 - h1 >= 1e-6)        {            mid = (h1 + h2) / 2;        /*    if (abs(p * mid * (r1 * r1 + r1 * ((r1+r2)/h * mid) + ((r1+r2)/h * mid) * ((r1+r2)/h * mid)) / 3 - v) <= 1e-6)            {                break;            }*/            double tmp=p * mid * (r1 * r1 + r1 * ((r2-r1)/h * mid+r1) + ((r2-r1)/h * mid+r1) *((r2-r1)/h * mid+r1)) / 3;            if (tmp <= v)            {                h1 = mid;            }            else            {                h2 = mid;            }           // printf("%f %f\n",h1,h2);            //getchar();        }         printf("%.6f\n", h1);    }    return 0;}

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