luogu1089【2004提高】津津的储蓄计划(模拟)

#include<cstdio>int a,b,s=0,n,ans=0,i,flag=0;int main(){    //freopen("a.in","r",stdin);    for(i=1;i<=12;i++){        scanf("%d",&a);        b=300+s-a;        if(b<0) {        flag=1;break;}        else {        n=b/100;        ans=ans+n;        s=b-n*100;        }    }    if(flag==1) printf("-%d",i);    else printf("%d",ans=ans*120+s);    return 0;}