写一个功能函数实现从数组中找出两个值相加等于某一个值，要求时间复杂度为 n;

#include<iostream>

usingnamespacestd;

voidFunc(intarray[],intlength,intthenumber, int&num1, int&num2)

{

       inthead = 0;

       inttail =length- 1;

       while(head != tail)

       {

              inttemp =array[head] +array[tail];

              if(temp ==thenumber)

              {

                     num1=array[head];

                     num2=array[tail];

                     cout<<num1<<'\t'<<num2<<endl;

                     head++;

                     tail--;

                     continue;

              }

              if(temp >thenumber)

                     tail--;

              else

                     head++;

       }

}

intmain()

{

       intabc[] = { 0,1,3,5,6,8,9,11,12,13,14,15,16 };

       intlength =sizeof(abc) /sizeof(abc[0]);

       inta, b;

       Func(abc, length,15, a, b);

       getchar();

   return0;

}