[PAT]1012. The Best Rank (25)@Java

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1012. The Best Rank (25)

时间限制
400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

To evaluate the performance of our first year CS majored students, we consider their grades of three courses only: C - C Programming Language, M - Mathematics (Calculus or Linear Algebra), and E - English. At the mean time, we encourage students by emphasizing on their best ranks -- that is, among the four ranks with respect to the three courses and the average grade, we print the best rank for each student.

For example, The grades of C, M, E and A - Average of 4 students are given as the following:

StudentID  C  M  E  A310101     98 85 88 90310102     70 95 88 84310103     82 87 94 88310104     91 91 91 91

Then the best ranks for all the students are No.1 since the 1st one has done the best in C Programming Language, while the 2nd one in Mathematics, the 3rd one in English, and the last one in average.

Input

Each input file contains one test case. Each case starts with a line containing 2 numbers N and M (<=2000), which are the total number of students, and the number of students who would check their ranks, respectively. Then N lines follow, each contains a student ID which is a string of 6 digits, followed by the three integer grades (in the range of [0, 100]) of that student in the order of C, M and E. Then there are M lines, each containing a student ID.

Output

For each of the M students, print in one line the best rank for him/her, and the symbol of the corresponding rank, separated by a space.

The priorities of the ranking methods are ordered as A > C > M > E. Hence if there are two or more ways for a student to obtain the same best rank, output the one with the highest priority.

If a student is not on the grading list, simply output "N/A".

Sample Input
5 6310101 98 85 88310102 70 95 88310103 82 87 94310104 91 91 91310105 85 90 90310101310102310103310104310105999999
Sample Output
1 C1 M1 E1 A3 AN/A



package go.jacob.day829;import java.util.Arrays;import java.util.Collection;import java.util.Comparator;import java.util.HashMap;import java.util.List;import java.util.Map;import java.util.Scanner;public class Demo2 {// 建立map,保存ID和学生的映射关系static Map<String, Student> map;static Scanner sc;public static void main(String[] args) {sc = new Scanner(System.in);int N = sc.nextInt();int M = sc.nextInt();Student[] stu = new Student[N];// 初始化init(stu, N);// solve函数用来计算每个学生的bestRank和bestCoursefor (int i = 0; i < N; i++) {solve(stu[i], N);}for (int i = 0; i < N; i++) {map.put(stu[i].ID, stu[i]);}String[] IDs = new String[M];for (int i = 0; i < M; i++) {IDs[i] = sc.next();}for (int i = 0; i < M; i++) {if (map.containsKey(IDs[i])) {Student student = map.get(IDs[i]);System.out.println(student.bestRank + " " + student.bestCourse);} elseSystem.out.println("N/A");}}/* * 初始化学生,各个科目排序完成的数组 */private static void init(Student[] stu, int N) {map = new HashMap<String, Student>();Student.cSeq = new Integer[N];Student.mSeq = new Integer[N];Student.eSeq = new Integer[N];Student.aSeq = new Integer[N];for (int i = 0; i < N; i++) {String ID = sc.next();int c = sc.nextInt(), m = sc.nextInt(), e = sc.nextInt();stu[i] = new Student(ID, c, m, e);map.put(stu[i].ID, stu[i]);}Collection<Student> lists=map.values();int i=0;for(Student s:lists){Student.cSeq[i]=s.scores[0];Student.mSeq[i]=s.scores[1];Student.eSeq[i]=s.scores[2];Student.aSeq[i]=s.scores[3];i++;}// 自定义比较器,实现从大到小排序Comparator<Integer> c = new Comparator<Integer>() {@Overridepublic int compare(Integer o1, Integer o2) {return o2 - o1;}};Arrays.sort(Student.cSeq, c);Arrays.sort(Student.mSeq, c);Arrays.sort(Student.eSeq, c);Arrays.sort(Student.aSeq, c);}private static void solve(Student stu, int N) {int min = 5;for (int i = 0; i < N; i++) {// 优先级A>C>M>Eif (stu.scores[3] == Student.aSeq[i] && i < min) {stu.bestCourse = "A";stu.bestRank = i;min = i;break;}if (stu.scores[0] == Student.cSeq[i] && i < min) {stu.bestCourse = "C";stu.bestRank = i;min = i;break;}if (stu.scores[1] == Student.mSeq[i] && i < min) {stu.bestCourse = "M";stu.bestRank = i;min = i;break;}if (stu.scores[2] == Student.eSeq[i] && i < min) {stu.bestCourse = "E";stu.bestRank = i;min = i;break;}}stu.bestRank = min + 1;}static class Student {public static Integer[] cSeq;public static Integer[] mSeq;public static Integer[] eSeq;public static Integer[] aSeq;String ID;int scores[] = new int[4];// 记录每个科目分数int bestRank;// 记录最高排名String bestCourse;// 记录最高排名课程public Student(String ID, int a, int b, int c) {super();this.ID = ID;scores[0] = a;scores[1] = b;scores[2] = c;scores[3] = (a + b + c) / 3;// 初始化为-1}}}/* *  * 5 6 310101 98 85 88 310102 70 95 88 310103 82 87 94 310104 91 91 91 310105 85 * 90 90 310101 310102 310103 310104 310105 999999 */


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