no known conversion for argument 1 from 'class-name' to 'class-name&'
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声明复制构造函数,参数需要const修饰,若没有const修饰在VS编译环境下可以通过,但是Linux下使用g++编译,则会报错。
template<class TYPE>
class SmartPtr
{
public:
TYPE* m_pData;
public:
SmartPtr()
{
m_pData = NULL;
}
SmartPtr(const SmartPtr<TYPE> &v)
{
m_pData = v.m_pData;
}
template<class TYPE>
class SmartPtr
{
public:
TYPE* m_pData;
public:
SmartPtr()
{
m_pData = NULL;
}
SmartPtr(const SmartPtr<TYPE> &v)
{
m_pData = v.m_pData;
}
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