Codeforces 845A Chess Tourney

A. Chess Tourney

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Berland annual chess tournament is coming!

Organizers have gathered 2·n chess players who should be divided into two teams withn people each. The first team is sponsored by BerOil and the second team is sponsored by BerMobile. Obviously, organizers should guarantee the win for the team of BerOil.

Thus, organizers should divide all 2·n players into two teams withn people each in such a way that the first team always wins.

Every chess player has its rating r_i. It is known that chess player with the greater rating always wins the player with the lower rating. If their ratings are equal then any of the players can win.

After teams assignment there will come a drawing to form n pairs of opponents: in each pair there is a player from the first team and a player from the second team. Every chess player should be in exactly one pair. Every pair plays once. The drawing is totally random.

Is it possible to divide all 2·n players into two teams withn people each so that the player from the first team in every pair winsregardless of the results of the drawing?

Input

The first line contains one integer n (1 ≤ n ≤ 100).

The second line contains 2·n integers a₁, a₂, ...a_2n (1 ≤ a_i ≤ 1000).

Output

If it's possible to divide all 2·n players into two teams withn people each so that the player from the first team in every pair wins regardless of the results of the drawing, then print"YES". Otherwise print "NO".

Examples

Input

21 3 2 4

Output

YES

Input

13 3

Output

NO

题目大意：把2n个数，等分成两组，能不能一组的任意个比另一组的任意一个数都大。

一开始觉得这题很难，然后写了一下发现排一下序就行了.....排序后，如果第一组的最后一个比第二组的最后一个小就可以YES了

#include<bits/stdc++.h>using namespace std;int num[500];int main(){int n;cin>>n;for(int i=0;i<2*n;i++) scanf("%d",&num[i]);sort(num,num+2*n);if(num[n-1]<num[n]) cout<<"YES"<<endl;else cout<<"NO"<<endl;}