PAT 乙级 1018

特别注意的是在一方哪种情况下都没赢时，输出B

#include<iostream>#include<cstring>#include<algorithm>using namespace std;int main(){int n;cin>>n;int m=n;char a,b;int a1=0,a2=0,a3=0;int g[100]={0};int h[100]={0};while(n--){cin>>a>>b;if(a!=b){if(a=='C'&&b=='J'){   a1++;   g[a-'0']++;}  if(a=='B'&&b=='C'){a1++;g[a-'0']++;}if(a=='J'&&b=='B'){a1++;g[a-'0']++;}if(a=='B'&&b=='J'){a3++;h[b-'0']++;}if(a=='C'&&b=='B'){a3++;h[b-'0']++;}if(a=='J'&&b=='C'){a3++;h[b-'0']++;}  } else  a2++;    }        cout<<a1<<" "<<a2<<" "<<a3<<endl;cout<<a3<<" "<<a2<<" "<<a1<<endl;int max1=-1;int max2=-1;int p,q;for(int i=0;i<100;i++){if(g[i]>max1){max1=g[i];p=i;}  if(h[i]>max2){max2=h[i];q=i; } }if(p==0)  cout<<"B"<<" ";else  cout<<char(p+'0')<<" ";if(q==0)  cout<<"B";else  cout<<char(q+'0')<<endl;         return 0;}