酒瓶和啤酒的问题

一、题目

每瓶啤酒2元，2个空酒瓶或4个瓶盖可换1瓶啤酒。10元最多可喝多少瓶啤酒？

二、程序

package test;public class Solution {public static int all = 5;public static int leftBottle;public static int leftTop;public static void main(String[] args) {all = all + drink(5,5);System.out.println("总共能喝"+all);System.out.println("剩下酒瓶个数"+leftBottle);System.out.println("剩下盖子个数"+leftTop);}public static int drink(int bottle, int top) {if(bottle >=2 || top >=4){leftBottle = (bottle/2)+(bottle%2)+(top/4);leftTop = (top/4) + (top%4) + (bottle/2);return  (bottle/2) + (top/4) + drink(leftBottle,leftTop);}return 0; }}

执行结果如下

总共能喝15剩下酒瓶个数1剩下盖子个数3