UVA 10935

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/*    思路:简单的模拟,用队列的功能即可,将头牌丢弃,下一张牌放到最后,一直重复该动作*/import java.util.LinkedList;import java.util.Scanner;public class Main{public static void main(String[] args) {Scanner cin = new Scanner(System.in);LinkedList<Integer> list = new LinkedList<>();while(cin.hasNext()){int n = cin.nextInt();if(n==0)break;if(n==1){System.out.println("Discarded cards:");System.out.println("Remaining card: 1");continue;}for(int i=1;i<=n;++i)list.add(i);int arr[]=new int[n];int len = list.size()-1;for(int i=0;i<len;++i){arr[i]=list.poll();list.add(list.poll());}System.out.print("Discarded cards: ");for(int i=0;i<len-1;++i)System.out.print(arr[i]+", ");System.out.println(arr[len-1]);System.out.println("Remaining card: "+list.poll());}}}



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