LeetCode
来源:互联网 发布:自己的淘宝店铺在哪里 编辑:程序博客网 时间:2024/06/15 18:17
Q:
In MATLAB, there is a very useful function called ‘reshape’, which can reshape a matrix into a new one with different size but keep its original data.
You’re given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number and column number of the wanted reshaped matrix, respectively.
The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were.
If the ‘reshape’ operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.
Example 1:
Input: nums = [[1,2], [3,4]]r = 1, c = 4Output: [[1,2,3,4]]Explanation:The row-traversing of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by using the previous list.
Example 2:
Input: nums = [[1,2], [3,4]]r = 2, c = 4Output: [[1,2], [3,4]]Explanation:There is no way to reshape a 2 * 2 matrix to a 2 * 4 matrix. So output the original matrix.
Note:
The height and width of the given matrix is in range [1, 100].
The given r and c are all positive.
A:
class Solution(object): def matrixReshape(self, nums, r, c): """ :type nums: List[List[int]] :type r: int :type c: int :rtype: List[List[int]] """ numsList = [] for i in nums: for j in i: numsList.append(j) if len(numsList) != r * c: return nums rowList = [] for i in range(r): colList = [] for j in range(c): colList.append(numsList[i*c+j]) rowList.append(colList) return rowList
- leetcode
- [leetcode]
- LeetCode
- leetcode
- leetcode
- leetcode:
- leetcode:
- LeetCode
- leetcode
- LEETCODE
- leetcode
- leetCode
- leetcode
- [leetcode]
- LeetCode
- leetcode
- leetcode:
- leetcode
- 理解HTTP协议
- httpclient工具类
- 路径问题
- 常见采样方法
- 使用Visual Studio Code搭建TypeScript开发环境
- LeetCode
- Spark源码分析之TaskSchedule和SparkDeployScheduleBackended的初始化
- NY54
- PAT-1046(划拳)
- winscp 登陆ubuntu服务器问题
- 虚拟机和容器的区别
- 次短路与k短路
- Android闹钟的一些注意事项
- 【双系统】Win10引导Ubuntu