【LeetCode算法练习（C语言）】Two Sum

题目：
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

链接：Two Sum

解法：穷举，时间O(n^2)

int* twoSum(int* nums, int numsSize, int target) {    int *ret = (int *)malloc(2 * sizeof(int));    for (int i = 0; i < numsSize; i++) {        for (int j = i + 1; j < numsSize; j++) {            if (nums[i] + nums[j] == target) {                ret[0] = i;                ret[1] = j;                return ret;            }        }    }    return ret;}

Runtime: 156 ms