jquery的ajax后台后去数据的table切换

来源：互联网发布：qt 调用dotnet 编程编辑：程序博客网时间：2024/05/29 07:03

<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title></title>
<style type="text/css">

*{
margin: 0;
padding: 0;
}
span{
display: inline-block;
width: 100px;
height: 50px;
background-color: gray;
border: 1px solid red;
text-align: center;
line-height: 50px;
}
.main{
width: 410px;
height: 400px;
/*background-color: red;*/
position: relative;
}
.main img{
width: 410px;
height: 400px
}
.main p{
width: 410px;
height: 50px;
background-color: black;
opacity: 0.5;
text-align: center;
font-size: 20px;
line-height: 50px;
position: absolute;
bottom: 0;
color: white;
}
.img_div{
display: none;
}
</style>
</style>
</head>
<body>
<div class="show">
<div class="btn">
<span>第一块</span><span>第二块</span><span>第三块</span><span>第四块</span>
</div>
<div class="main">

</div>
</div>

</body>
<script src="js/jquery-3.2.1.min.js" ></script>
<script type="text/javascript">
//后台获取数据
$.ajax({
url:'http://localhost/AJAX/php/img.php',
type:'post',
data:{type:''},
success:function(res){

console.log(res);
var arr= JSON.parse(res);
console.log(arr);
//创建节点加载图片
for(var i=0;i<arr.length;i++){
var myDiv=$('<div class="img_div"></div>');
myDiv.html('<img src="'+arr[i].url+'"><p>'+arr[i].title+'<p>');
$('.main').append(myDiv);

}
$('.img_div').eq(0).css({'display':'block'});
},
async:true
});
/*..................table切换.........................*/

//绑定按钮事件
$('span').on('click',function(){

$(this).css({'backgroundColor':'red'}).siblings().css({'backgroundColor':'gray'});

$('.img_div').eq($(this).index()).css({'display':'block'}).siblings().css({'display':'none'});
});
</script>
</html>

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