hdu 3746 Cyclic Nacklace
来源:互联网 发布:aes算法有哪些 编辑:程序博客网 时间:2024/05/24 01:20
Problem Description
CC always becomes very depressed at the end of this month, he has checked his credit card yesterday, without any surprise, there are only 99.9 yuan left. he is too distressed and thinking about how to tide over the last days. Being inspired by the entrepreneurial spirit of “HDU CakeMan”, he wants to sell some little things to make money. Of course, this is not an easy task.
As Christmas is around the corner, Boys are busy in choosing christmas presents to send to their girlfriends. It is believed that chain bracelet is a good choice. However, Things are not always so simple, as is known to everyone, girl’s fond of the colorful decoration to make bracelet appears vivid and lively, meanwhile they want to display their mature side as college students. after CC understands the girls demands, he intends to sell the chain bracelet called CharmBracelet. The CharmBracelet is made up with colorful pearls to show girls’ lively, and the most important thing is that it must be connected by a cyclic chain which means the color of pearls are cyclic connected from the left to right. And the cyclic count must be more than one. If you connect the leftmost pearl and the rightmost pearl of such chain, you can make a CharmBracelet. Just like the pictrue below, this CharmBracelet’s cycle is 9 and its cyclic count is 2:
Now CC has brought in some ordinary bracelet chains, he wants to buy minimum number of pearls to make CharmBracelets so that he can save more money. but when remaking the bracelet, he can only add color pearls to the left end and right end of the chain, that is to say, adding to the middle is forbidden.
CC is satisfied with his ideas and ask you for help.
Input
The first line of the input is a single integer T ( 0 < T <= 100 ) which means the number of test cases.
Each test case contains only one line describe the original ordinary chain to be remade. Each character in the string stands for one pearl and there are 26 kinds of pearls being described by ‘a’ ~’z’ characters. The length of the string Len: ( 3 <= Len <= 100000 ).
Output
For each case, you are required to output the minimum count of pearls added to make a CharmBracelet.
Sample Input
3
aaa
abca
abcde
Sample Output
0
2
5
Author
possessor WC
Source
HDU 3rd “Vegetable-Birds Cup” Programming Open Contest
学习了一波kmp,必须得深刻了解next数组的含义才行啊
#include <iostream>#include <stdio.h>#include <string.h>#include <algorithm>#include <math.h>char a[110000];int nextt[110000];int h;using namespace std;void getnext(){ int i = -1, j = 0; nextt[0] = -1; while(j < h) { if(i == -1 || a[i] == a[j]) { i++; j++; nextt[j] = i; } else { i = nextt[i]; } }}int main(){ int t; scanf("%d",&t); while(t--) { scanf("%s",a); h =strlen(a); getnext(); int len = h - nextt[h]; if(len != h && h % len == 0) { printf("0\n"); continue; } else { int ans = len - nextt[h] % len; printf("%d\n",ans); } }}
- HDU-3746 Cyclic Nacklace
- HDU 3746 Cyclic Nacklace
- hdu 3746 Cyclic Nacklace
- hdu 3746 Cyclic Nacklace
- HDU 3746 Cyclic Nacklace
- hdu 3746 Cyclic Nacklace
- HDU-Cyclic Nacklace-3746
- hdu 3746 Cyclic Nacklace
- hdu 3746 Cyclic Nacklace
- hdu 3746 Cyclic Nacklace
- hdu 3746 Cyclic Nacklace
- hdu 3746 Cyclic Nacklace
- HDU 3746 Cyclic Nacklace
- HDU 3746 Cyclic Nacklace
- hdu 3746 Cyclic Nacklace
- hdu 3746 Cyclic Nacklace
- HDU 3746 Cyclic Nacklace
- HDU 3746 Cyclic Nacklace
- angular之表单验证ngMessages
- 初识动态代理(值得深入研究的知识点)
- [LeetCode-Algorithms-1] "Two Sum" (2017.9.8)
- 米语录学习(三)
- Event Kernel mode
- hdu 3746 Cyclic Nacklace
- Advanced Programming in Unix Environment Episode 1
- 关注的blogs
- 1007. Maximum Subsequence Sum (25)
- poj1979-Red and Black
- 使用循环分别实现将十进制整数和小数变成二进制数
- Redis基础、高级特性与性能调优
- tab切换各种不同的解决方案
- 数据库基础学习day3(对数据的增删改查)