1002. A+B for Polynomials (25)
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1002. A+B for Polynomials (25)
时间限制
400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
This time, you are supposed to find A+B where A and B are two polynomials.
Input
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.
Output
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input2 1 2.4 0 3.22 2 1.5 1 0.5Sample Output
3 2 1.5 1 2.9 0 3.2
#include<cstdio>#include<cstring>using namespace std;int main(){ int exp[1100]; double coe[1100]; memset(exp, 0 ,sizeof(exp)); memset(coe, 0, sizeof(coe)); int n, m; scanf("%d", &n); int ai; double ni; while(n--) { scanf("%d%lf", &ai, &ni); coe[ai] +=ni; } scanf("%d", &m); while(m--) { scanf("%d%lf", &ai, &ni); coe[ai] +=ni; } int cnt = 0; for( int i = 1000; i >= 0; i--) { if(coe[i] != 0) { cnt++; } } printf("%d",cnt); int num = 0; for( int i = 1000; i >= 0; i--) { if(coe[i] != 0) { printf(" %d %.1f", i, coe[i]); } }}
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