1002. A+B for Polynomials (25)

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1002. A+B for Polynomials (25)

时间限制
400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input
2 1 2.4 0 3.22 2 1.5 1 0.5
Sample Output
3 2 1.5 1 2.9 0 3.2
#include<cstdio>#include<cstring>using namespace std;int main(){   int exp[1100];   double coe[1100];   memset(exp, 0 ,sizeof(exp));   memset(coe, 0, sizeof(coe));   int n, m;   scanf("%d", &n);   int ai;   double ni;   while(n--)   {       scanf("%d%lf", &ai, &ni);       coe[ai] +=ni;   }   scanf("%d", &m);   while(m--)   {      scanf("%d%lf", &ai, &ni);       coe[ai] +=ni;   }   int cnt = 0;   for( int i = 1000; i >= 0; i--)   {       if(coe[i] != 0)       {          cnt++;       }   }   printf("%d",cnt);   int num = 0;      for( int i = 1000; i >= 0; i--)   {       if(coe[i] != 0)       {          printf(" %d %.1f", i, coe[i]);       }   }}