1121. Damn Single (25)

时间限制

300 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

"Damn Single (单身狗)" is the Chinese nickname for someone who is being single. You are supposed to find those who are alone in a big party, so they can be taken care of.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (<=50000), the total number of couples. Then N lines of the couples follow, each gives a couple of ID's which are 5-digit numbers (i.e. from 00000 to 99999). After the list of couples, there is a positive integer M (<=10000) followed by M ID's of the party guests. The numbers are separated by spaces. It is guaranteed that nobody is having bigamous marriage (重婚) or dangling with more than one companion.

Output Specification:

First print in a line the total number of lonely guests. Then in the next line, print their ID's in increasing order. The numbers must be separated by exactly 1 space, and there must be no extra space at the end of the line.

Sample Input:

311111 2222233333 4444455555 66666755555 44444 10000 88888 22222 11111 23333

Sample Output:

510000 23333 44444 55555 88888

注意控制格式  %05d 检查了半天。。。

#include<stdio.h>#include<map>#include<set>#include<vector>using namespace std;map<int,int>couple;set<int>temp,ans;vector<int>name;int main(){int n,m,i,p1,p2,query;scanf("%d",&n);for(i=0;i<n;i++){scanf("%d %d",&p1,&p2);couple[p1]=p2; couple[p2]=p1;}scanf("%d",&m);for(i=0;i<m;i++){scanf("%d",&query);temp.insert(query); name.push_back(query);}int lover;for(i=0;i<m;i++){lover=couple[name[i]];if(lover==0){//lover为0有两种情况，1.对象就是00000  2.对象不存在 if(couple[0]!=name[i]){//对应第2种情况 ans.insert(name[i]);continue;}}if(temp.find(lover)==temp.end()){ans.insert(name[i]);}}printf("%d\n",ans.size());set<int>::iterator it=ans.begin();int flag=0;for(;it!=ans.end();it++){if(flag==0){printf("%05d",*it);flag=1;}else{printf(" %05d",*it);}}}