Python3：range()函数

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• 转载请注明作者和出处：http://blog.csdn.net/u011475210
• 操作系统：WINDOWS 10
• 软件版本：python-3.6.2-amd64
• 编  者：WordZzzz

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Python2.x中range()函数：

  老规矩，help！

>>> help(range)Help on built-in function range in module __builtin__:range(...)    range(stop) -> list of integers    range(start, stop[, step]) -> list of integers    Return a list containing an arithmetic progression of integers.    range(i, j) returns [i, i+1, i+2, ..., j-1]; start (!) defaults to 0.    When step is given, it specifies the increment (or decrement).    For example, range(4) returns [0, 1, 2, 3].  The end point is omitted!    These are exactly the valid indices for a list of 4 elements.

  可以看出，在Python2.x中，range()返回的是可以用来迭代的列表。

Python3.x中range()函数：

  同样，help！

>>> help(range)Help on class range in module builtins:class range(object) |  range(stop) -> range object |  range(start, stop[, step]) -> range object | |  Return an object that produces a sequence of integers from start (inclusive) |  to stop (exclusive) by step.  range(i, j) produces i, i+1, i+2, ..., j-1. |  start defaults to 0, and stop is omitted!  range(4) produces 0, 1, 2, 3. |  These are exactly the valid indices for a list of 4 elements. |  When step is given, it specifies the increment (or decrement).

  啊哦，在Python3.x中，range()返回的是一个range对象。

样例对比：

Python2.x：

>>> range(1,10)[1, 2, 3, 4, 5, 6, 7, 8, 9]

Python3.x：

>>> range(1,10)range(1, 10)>>> list(range(1,10))[1, 2, 3, 4, 5, 6, 7, 8, 9]

  通过list强制类型转换，可以在Python3.x中实现Python2.x中的range函数一样的效果。

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