SQLite 中的递归

create table if not exists testTable( id INT PRIMARY KEY,[name] NVARCHAR(20), parentId INT );INSERT INTO testTable(id,[name],parentId) VALUES(1,'xf1',0);INSERT INTO testTable(id,[name],parentId) VALUES(2,'xf2',0);INSERT INTO testTable(id,[name],parentId) VALUES(3,'xf3',2);INSERT INTO testTable(id,[name],parentId) VALUES(4,'xf4',3);INSERT INTO testTable(id,[name],parentId) VALUES(5,'xf5',4);INSERT INTO testTable(id,[name],parentId) VALUES(6,'xf6',5);WITH RECURSIVE   cte(id,name,parentId) AS(    SELECT id,name,parentId FROM testTable WHERE id='6'    UNION ALL    SELECT a.id,a.name,a.parentId FROM testTable AS a INNER JOIN         cte ON a.id=cte.parentId   )SELECT * FROM cte;

--得到1-10 的数WITH RECURSIVE  cnt(x) AS (VALUES(1) UNION ALL SELECT x+1 FROM cnt WHERE x<10)SELECT x FROM cnt order by x;WITH RECURSIVE  cnt(x) AS (     SELECT 1     UNION ALL     SELECT x+1 FROM cnt      LIMIT 10  )SELECT x FROM cnt order by x;

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