问题总结

1.C++类的构造函数和析构函数，可以写在外面：

#include <iostream>using namespace std;class String{    char *str;    int Num[20];    int Count;public:    String(char *s);    ~String();    void Process();    void Show();};String::String(char *s) {    if(s){        str= new char [strlen(s)+1];        str= strcpy(str,s);    }else{        str = 0;    }    Count = 0;}String::~String() {    delete [] str;}void String::Process() {    int i=0,n;    char *p= str;    while (*p){        while(*p>='0'&&*p<'9'&&*p){            n=n*10+(*p-'a');            p++;        }        Num[i++]=n;    }    Count = i;}

2.C++的可以换行写，不影响编译：

#include <iostream>using namespace std;int main(){    int a[15]={1,2,3,4,5,6,7,               8,9,0,1,2,3         //这么写没毛病            ,4,5};    for (int i=0;i<15;i++){ cout<<a[i]<<endl; }            //一句话的代码建议这么写，考试时候看起来方便，括号不至于太多    return 0;}

3.重载函数的类外实现

#include <iostream>using namespace std;class Complex{    float Real,Image;public:    Complex(){Real=0;Image=0;}    Complex(float r,float i){Real=r; Image=i;}    void Print(){        cout<<Real;        if(Image>0){cout<<"+";}        if(Image!=0){cout<<Image<<"i";}        cout<<endl;    }    Complex operator=(Complex c){        Real = c.Real;        Image = c.Image;        return *this;    }    Complex operator,(Complex c);};Complex Complex::operator,(Complex c){    Complex t;    t.Real = Real;    t.Image = Image;    return t;}int main(){    Complex c1(3.4,5.6),c2(10.5,-12.3),c3;    c1.Print();    c2.Print();    c3=(c1,c2);    c3.Print();    return 0;}

4.字符串输出问题：

#include <iostream>using namespace std;int main(){    char s[]="Rep\0ch";    int m=sizeof(s);    cout<<"m="<<m<<endl;    cout<<"输出字符串："<<endl;    for (int i=0;i<sizeof(s);i++){        cout<<s[i]<<endl;    }    return 0;}

输出的结果是：

m=7
输出字符串：
R
e
p
♦️
c
h
♦️


Process finished with exit code 0