【CUGBACM15级BC第36场 A】hdu 5198 Strange Class

Strange Class

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1234    Accepted Submission(s): 641

Problem Description

In Vivid’s school, there is a strange class(SC). In SC, the students’ names are very strange. They are in the same format:anbncn(a,b,c must not be the same with each other). For example studens whose names are“abc”,”ddppqq” are in SC, however studens whose names are “aaa”,“ab”,”ddppqqq” are not in SC.
Vivid makes friends with so many students, he wants to know who are in SC.

 

Input

There are multiple test cases (about 10), each case will give a string S which is the name of Vivid’s friend in a single line.
Please process to the end of file.

[Technical Specification]

1≤|S |≤10.

|S| indicates the length of S.

S only contains lowercase letter.

 

Output

For each case, output YES if Vivid’s friend is the student of SC, otherwise output NO.

 

Sample Input

abcbc

 

Sample Output

YESNO

 

题意：问给出的字符串是否是三个不同字符组成的，三个字符可以有多个。但是注意要连续，比如ababcc是不合法的

思路：简单题，直接模拟

#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>#include <cmath>using namespace std;char a[15];int solve(int len){    if (a[0] == a[len] || a[0] == a[len * 2] || a[len] == a[len * 2])    {        return 0;    }    for (int i = 1; i < len; i++)        if (a[i] != a[i - 1])        {            return 0;        }    for (int i = len + 1; i < 2 * len; i++)        if (a[i] != a[i - 1])        {            return 0;        }    for (int i = 2 * len + 1; i < 3 * len; i++)        if (a[i] != a[i - 1])        {            return 0;        }    return 1;}int main(){    while (~scanf("%s", a))    {        int len = strlen(a);        if (len % 3 != 0)        {            printf("NO\n");            continue;        }        int ans = solve(len / 3);        if (ans)        {            printf("YES\n");        }        else        {            printf("NO\n");        }    }    return 0;}