Fizz Buzz

https://leetcode.com/problems/fizz-buzz/description/
给出一个数，输出1~n的字符串，15的倍数输出FizzBuzz，3的倍数输出Fizz，5的倍数输出Buzz

class Solution {    public List<String> fizzBuzz(int n) {        List<String> list = new ArrayList<String>();        while(n > 0) {            if(n % 15 == 0)                list.add("FizzBuzz");            else if(n % 3 == 0) {                list.add("Fizz");            }else if(n % 5 == 0) {                list.add("Buzz");            }else                list.add(String.valueOf(n));            n--;        }        Collections.reverse(list);        return list;    }}