杭电1039题题解



水题//
题目大意就是给你一个字符串，让你判断符不符合以下三个条件：
1.它必须包含至少一个元音。
2.它不能包含三个连续的元音或三个连续的辅音。
3.除了“ee”或“oo”之外，它不能包含两个连续出现的字母。
#include<iostream>#include<cstring>using namespace std;int ruler1(char[]);int ruler2(char[]);int ruler3(char[]);int judge_yuan(char);int main(){ char code[22]={'\0'}; cin>>code; while(strcmp(code,"end")) { int judge=ruler1(code)+ruler2(code)+ruler3(code); if(judge==3)     cout<<"<"<<code<<"> is acceptable."<<endl; else    cout<<"<"<<code<<"> is not acceptable."<<endl; int i; for(i=0;code[i];i++)  //清空     code[i]='\0'; cin>>code; } } int ruler1(char code[]) { int i;     for(i=0;code[i];i++)    {   if(judge_yuan(code[i]))         return 1;    }     return 0; }int judge_yuan(char a){if(a=='a'||a=='e'||a=='i'||a=='o'||a=='u')     return 1;     else        return 0; }   int ruler2(char code[]) { int i; for(i=1;code[i];i++) { if(code[i]==code[i-1]&&code[i]!='e'&&code[i]!='o')       return 0; } return 1; } int ruler3(char code[]) { int head=0,tail=1; int i; while((tail-head)<=2&&code[tail]) { if(judge_yuan(code[head])==judge_yuan(code[tail]))   {      tail++;       } else      {      head=tail;      tail++;  } }  if(tail-head==3)                //注意这里的判断条件，很容易弄错     return 0;else   return 1; }