hdu 6213-Chinese Zodiac (map)

Problem Description
The Chinese Zodiac, known as Sheng Xiao, is based on a twelve-year cycle, each year in the cycle related to an animal sign. These signs are the rat, ox, tiger, rabbit, dragon, snake, horse, sheep, monkey, rooster, dog and pig.
Victoria is married to a younger man, but no one knows the real age difference between the couple. The good news is that she told us their Chinese Zodiac signs. Their years of birth in luner calendar is not the same. Here we can guess a very rough estimate of the minimum age difference between them.
If, for instance, the signs of Victoria and her husband are ox and rabbit respectively, the estimate should be 2 years. But if the signs of the couple is the same, the answer should be 12 years.

Input
The first line of input contains an integer T (1≤T≤1000) indicating the number of test cases.
For each test case a line of two strings describes the signs of Victoria and her husband.

Output
For each test case output an integer in a line.

Sample Input
3
ox rooster
rooster ox
dragon dragon

Sample Output
8
4
12

给出两个人的属相，后面那个人的年龄大，问两人的年龄差

#include <iostream>#include <cstdio>#include <string>#include <map>using namespace std;map<string,int> ma;int main(){    ma["rat"]=1;    ma["ox"]=2;    ma["tiger"]=3;    ma["rabbit"]=4;    ma["dragon"]=5;    ma["snake"]=6;    ma["horse"]=7;    ma["sheep"]=8;    ma["monkey"]=9;    ma["rooster"]=10;    ma["dog"]=11;    ma["pig"]=12;    int t;    cin>>t;    while(t--)    {        string a,b;        cin>>a>>b;        int s;        if(ma[a]<ma[b])        {            s=ma[b]-ma[a];        }        else        {            s=ma[b]-ma[a]+12;        }        printf("%d\n",s);    }    return 0;}