统计输入整数序列两两组合是7的倍数的个数

输入：第一行整数n，第二行n个整数

输出：两两组合可以被7整除的个数

#include <stdio.h>long long mergeinteger1(int a, int b){long long sum = 0;//if (b >= 0)  int mid = b;sum += a * 10;/*while (mid /= 10){sum *= 10;}*/for (; mid /= 10; sum *= 10);sum += b;return sum;}int main(){int n = 0;int i = 0;int j = 0;long long sum1 = 0;long long sum2 = 0;long long mid;int count = 0;int A[100000] = { 0 };scanf_s("%d", &n);for (i = 0; i<n; i++){scanf_s("%d", &A[i]);}for (i = 0; i<n; i++)for (j = i + 1; j<n; j++){printf("%lld   ", mergeinteger1(A[i], A[j]));printf("%lld  ", mergeinteger1(A[j], A[i]));if (mergeinteger1(A[i], A[j]) % 7 == 0)count++;if (mergeinteger1(A[j], A[i]) % 7 == 0)count++;}printf("%d\n", count);}