Polycarp's phone book
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对于001,1处理会出问题的情况,再所有的数字前面再加一个1,就变成1001和11,区分开来了,
itoa函数codefoeces上c++14才有
#include<iostream>#include<string.h>#include<stdio.h>#include<map>#include<string>#include<stdlib.h>using namespace std;char str[70000+10][10];char s[10];map<int,int> m;int n;void solve(char p[],int num){ for(int i=0;i<9;i++){ int v=1; for(int j=i;j<9;j++){ v=v*10+p[j]-'0'; if(m[v]==0) m[v]=num; else if(m[v]!=num) m[v]=-1; } }}void get_ans(char p[]){ int ans=0x7fffffff; for(int i=0;i<9;i++){ int v=1; for(int j=i;j<9;j++){ v=v*10+p[j]-'0'; if(m[v]!=0 && m[v]!=-1){ ans=min(ans,v); } } } itoa(ans,s,10); printf("%s\n",s+1);}int main(){ scanf("%d",&n); for(int i=1;i<=n;i++){ scanf("%s",str[i]); } m.clear(); for(int i=1;i<=n;i++){ solve(str[i],i); } for(int i=1;i<=n;i++){ get_ans(str[i]); }}
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