CUDA编程(1)
来源:互联网 发布:服务器域名查询 编辑:程序博客网 时间:2024/06/02 20:57
/** Copyright 1993-2010 NVIDIA Corporation. All rights reserved.** NVIDIA Corporation and its licensors retain all intellectual property and* proprietary rights in and to this software and related documentation.* Any use, reproduction, disclosure, or distribution of this software* and related documentation without an express license agreement from* NVIDIA Corporation is strictly prohibited.** Please refer to the applicable NVIDIA end user license agreement (EULA)* associated with this source code for terms and conditions that govern* your use of this NVIDIA software.**/#include "book.h"#define imin(a,b) (a<b?a:b)const int N = 33 * 1024;const int threadsPerBlock = 256;const int blocksPerGrid =imin(32, (N + threadsPerBlock - 1) / threadsPerBlock);__global__ void dot(float *a, float *b, float *c) { //对于每个block cache都产生一个副本 __shared__ float cache[threadsPerBlock]; int tid = threadIdx.x + blockIdx.x * blockDim.x; int cacheIndex = threadIdx.x; float temp = 0; while (tid < N) { temp += a[tid] * b[tid]; tid += blockDim.x * gridDim.x; } // set the cache values cache[cacheIndex] = temp; // 如果一个线程快的线程没有执行完syncthreads前的语句的话,不执行后面的语句 __syncthreads(); //块内线程释放 // for reductions, threadsPerBlock must be a power of 2 // because of the following code int i = blockDim.x / 2; while (i != 0) { if (cacheIndex < i) cache[cacheIndex] += cache[cacheIndex + i]; //确保前面线程已经OK __syncthreads(); i /= 2; } if (cacheIndex == 0) c[blockIdx.x] = cache[0];}int main(void) { float *a, *b, c, *partial_c; float *dev_a, *dev_b, *dev_partial_c; // allocate memory on the cpu side a = (float*)malloc(N*sizeof(float)); b = (float*)malloc(N*sizeof(float)); partial_c = (float*)malloc(blocksPerGrid*sizeof(float)); // allocate the memory on the GPU HANDLE_ERROR(cudaMalloc((void**)&dev_a, N*sizeof(float))); HANDLE_ERROR(cudaMalloc((void**)&dev_b, N*sizeof(float))); HANDLE_ERROR(cudaMalloc((void**)&dev_partial_c, blocksPerGrid*sizeof(float))); // fill in the host memory with data for (int i = 0; i<N; i++) { a[i] = i; b[i] = i * 2; } // copy the arrays 'a' and 'b' to the GPU HANDLE_ERROR(cudaMemcpy(dev_a, a, N*sizeof(float), cudaMemcpyHostToDevice)); HANDLE_ERROR(cudaMemcpy(dev_b, b, N*sizeof(float), cudaMemcpyHostToDevice)); dot << <blocksPerGrid, threadsPerBlock >> >(dev_a, dev_b, dev_partial_c); // copy the array 'c' back from the GPU to the CPU HANDLE_ERROR(cudaMemcpy(partial_c, dev_partial_c, blocksPerGrid*sizeof(float), cudaMemcpyDeviceToHost)); // finish up on the CPU side c = 0; for (int i = 0; i<blocksPerGrid; i++) { c += partial_c[i]; }#define sum_squares(x) (x*(x+1)*(2*x+1)/6) printf("Does GPU value %.6g = %.6g?\n", c, 2 * sum_squares((float)(N - 1))); // free memory on the gpu side HANDLE_ERROR(cudaFree(dev_a)); HANDLE_ERROR(cudaFree(dev_b)); HANDLE_ERROR(cudaFree(dev_partial_c)); // free memory on the cpu side free(a); free(b); free(partial_c); getchar();}
阅读全文
0 0
- CUDA编程(1)
- CUDA学习笔记(一) CUDA编程模型1
- cuda编程优化1
- CUDA编程实战-1
- Cuda编程结构《1》
- CUDA学习---(1) CUDA编程基本概念
- CUDA编程->CUDA入门了解(一)
- CUDA C 编程指导(二):CUDA编程模型详解
- 并行编程1:CUDA基础
- CUDA编程基础系列1
- CUDA-CODE5-并行编程(1)
- CUDA并行编程学习心得1
- cuda矩阵编程(一)
- CUDA编程实践(一)
- (CUDA 编程1).CUDA 线程执行模型分析(一)招兵 ------ GPU的革命
- 看cuda初级教程视频笔记(周斌讲的)--CUDA编程1
- CUDA编程
- cuda编程
- python strip()与rstrip() 方法
- 分布式事务方案:可靠消息最终一致方案
- TiDB 助力一面数据实现消费领域的决策分析平台
- Zookeeper学习笔记 --- Python实现向zookeeper中写入配置数据
- 树的知识点总结
- CUDA编程(1)
- 1072. 开学寄语(20)
- navicat提权的两个方法(注册表+星号查看器)
- 67 个节省开发者时间的实用工具、库与资源(前端向)
- VMware Workstation Pro 12.5.7虚拟机安装 MAC OS X El Capitan 10.11.1 (15B42).cdr懒人版
- java中有自动回收机制,为什么有时候还写程序回收?
- Linux 使用expect工具和scp命令实现自动复制传输文件
- Android 手机卫士(9)安装从服务器端下载好的APK
- 1013 三的幂的和