HDU1002 Sum Problem 大数 Java&&C

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题目链接:HDU1002

套用大数模板或者用JAVA写就行,很裸的题目。


Ccode:

/*2017年9月20日16:18:17HDU1002AC 大数模板  15MS 比JAVA快很多 */# include<stdio.h>  # include<string.h>  # include<malloc.h> #include <iostream>#include <map>#include <set>#include <string>#include <cstring>#include <cstdio>#include <algorithm>#include <cmath>#include <queue>#include <vector> using namespace std;typedef long long ll;void add(char* a,char* b,char* c)  {      int i,j,k,max,min,n,temp;      char *s,*pmax,*pmin;      max=strlen(a);      min=strlen(b);      if (max<min)      {          temp=max;          max=min;          min=temp;          pmax=b;          pmin=a;      }      else      {          pmax=a;          pmin=b;      }      s=(char*)malloc(sizeof(char)*(max+1));      s[0]='0';      for (i=min-1,j=max-1,k=max;i>=0;i--,j--,k--)          s[k]=pmin[i]-'0'+pmax[j];         for (;j>=0;j--,k--)             s[k]=pmax[j];      for (i=max;i>=0;i--)          if (s[i]>'9')          {              s[i]-=10;              s[i-1]++;          }      if (s[0]=='0')      {          for (i=0;i<=max;i++)              c[i-1]=s[i];             c[i-1]='\0';      }      else      {          for (i=0;i<=max;i++)              c[i]=s[i];             c[i]='\0';      }      free(s);  }    /*大数减法*/   void subtract(char* a,char* b,char* c)  {      int i,j,ca,cb;      ca=strlen(a);      cb=strlen(b);      if (ca>cb||(ca==cb&&strcmp(a,b)>=0))      {          for (i=ca-1,j=cb-1;j>=0;i--,j--)              a[i]-=(b[j]-'0');             for (i=ca-1;i>=0;i--)                 if (a[i]<'0')                 {                     a[i]+=10;                     a[i-1]--;              }          i=0;          while (a[i]=='0')              i++;             if (a[i]=='\0')            {                c[0]='0';                c[1]='\0';          }          else          {              for (j=0;a[i]!='\0';i++,j++)                  c[j]=a[i];                 c[j]='\0';          }      }      else      {          for (i=ca-1,j=cb-1;i>=0;i--,j--)              b[j]-=(a[i]-'0');             for (j=cb-1;j>=0;j--)                 if (b[j]<'0')                 {                     b[j]+=10;                     b[j-1]--;              }          j=0;          while (b[j]=='0')              j++;             i=1;             c[0]='-';             for (;b[j]!='\0';i++,j++)                 c[i]=b[j];            c[i]='\0';      }              }    /* 大数乘法*/   void multiply(char* a,char* b,char* c)  {      int i,j,ca,cb,* s;      ca=strlen(a);      cb=strlen(b);      s=(int*)malloc(sizeof(int)*(ca+cb));      for (i=0;i<ca+cb;i++)          s[i]=0;      for (i=0;i<ca;i++)          for (j=0;j<cb;j++)              s[i+j+1]+=(a[i]-'0')*(b[j]-'0');      for (i=ca+cb-1;i>=0;i--)          if (s[i]>=10)          {              s[i-1]+=s[i]/10;              s[i]%=10;          }      i=0;      while (s[i]==0)          i++;         for (j=0;i<ca+cb;i++,j++)             c[j]=s[i]+'0';      c[j]='\0';      free(s);  }    /*大数除法,返回余数*/  int dividor(char* a,int b,char* c)  {      int i,j,temp=0,n;      char* s;      n=strlen(a);      s=(char*)malloc(sizeof(char)*(n+1));      for (i=0;a[i]!=0;i++)         {             temp=temp*10+a[i]-'0';             s[i]=temp/b+'0';             temp%=b;      }      s[i]='\0';      for (i=0;s[i]=='0'&&s[i]!='\0';i++);      if (s[i]=='\0')      {          c[0]='0';          c[1]='\0';      }      else      {          for (j=0;s[i]!='\0';i++,j++)              c[j]=s[i];             c[j]='\0';      }      free(s);      return temp;  }  const int maxn=1010;char a[maxn],b[maxn],c[maxn];int main(){int t;scanf("%d",&t);//int kase=0;for(int i=1;i<=t;i++){scanf("%s%s",&a,&b);printf("Case %d:\n",i) ;add(a,b,c);printf("%s + %s = %s\n",a,b,c);if(i!=t) printf("\n");}return 0;} 


JAVA code:

/* * 2017年9月20日16:19:28 * HDU1002 * 大 数   327ms * AC*/import java.io.*;import java.util.*;import java.math.*;public class Main {public static void main(String []args){Scanner cin=new Scanner(new BufferedInputStream(System.in));PrintWriter cout=new PrintWriter(System.out);int t=cin.nextInt();for(int i=1;i<=t;i++){cout.println("Case "+i+":");BigInteger a,b,c;a=cin.nextBigInteger();b=cin.nextBigInteger();c=a.add(b);cout.println(a+" + "+b+" = "+c);if(i!=t)cout.println("");}cout.flush();}}



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