LBP等价模式

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图像特征LBP原理及C++实现可以直接参考小路孩的博客点击打开链接，博客中很详细的介绍了各种LBP特征的实现原理，并且有对应的C++代码。

补充一种CS-LBP（中心对称）实现：

#include <opencv2/opencv.hpp>  #include <iostream>  using namespace cv;using namespace std;Mat CSLBP(Mat & src, double * lbp_hist){Mat img;src.copyTo(img);uchar UTable[16];// 计算二进制表示，并通过查表的方式，获取其对应的等价模式下的值  for (int i = 1; i < img.rows - 1; i++){for (int j = 1; j < img.cols - 1; j++){uchar code = 0;for (int m = 0; m < 4; m++){code |= (src.at<uchar>(i - 1, j - 1) >= src.at<uchar>(i + 1, j + 1)) << 0;code |= (src.at<uchar>(i, j - 1) >= src.at<uchar>(i, j + 1)) << 1;code |= (src.at<uchar>(i + 1, j - 1) >= src.at<uchar>(i - 1, j + 1)) << 2;code |= (src.at<uchar>(i + 1, j) >= src.at<uchar>(i - 1, j)) << 3;}img.at<uchar>(i, j) = code;}}for (int i = 1; i < img.rows - 1; i++){for (int j = 1; j < img.cols - 1; j++){UTable[img.at<uchar>(i, j)]++;}}// 查找最大值  float max_hist_val = 0;for (int i = 0; i < 16; i++){if (max_hist_val < UTable[i]){max_hist_val = UTable[i];}}//cout << max_hist_val << endl;  for (int i = 0; i < 16; i++){lbp_hist[i] = 1.0 * UTable[i] / max_hist_val;//cout << "lbp_hist: " << lbp_hist[i] << endl;  }Mat LBP_hist = Mat::zeros(32, 17 * 2, CV_8U);Mat LBP_hist_color;cvtColor(LBP_hist, LBP_hist_color, COLOR_GRAY2BGR);for (int i = 0; i < 16; i++){cout << 1 - UTable[i] << endl;rectangle(LBP_hist_color,Point(i * 2, 32),Point((i + 1) * 2, int((1 - lbp_hist[i]) * 32)),Scalar(255, 0, 0));}return LBP_hist_color;}int main(){Mat src = imread("1.jpg");Mat gray;cvtColor(src, gray, CV_BGR2GRAY);double lbp_hist[16] = { 0 };Mat test = CSLBP(gray, lbp_hist);namedWindow("src", 0);resizeWindow("src", 300, 300);namedWindow("test", 0);resizeWindow("test", 300, 300);imshow("src", src);imshow("test", test);waitKey();return 0;}

效果如下：

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